Folds
Polars provides many expressions to perform computations across columns, like sum_horizontal
,
mean_horizontal
, and min_horizontal
. However, these are just special cases of a general
algorithm called a fold, and Polars provides a general mechanism for you to compute custom folds for
when the specialised versions of Polars are not enough.
Folds computed with the function fold
operate on the full columns for maximum speed. They utilize
the data layout very efficiently and often have vectorized execution.
Basic example
As a first example, we will reimplement sum_horizontal
with the function fold
:
import operator
import polars as pl
df = pl.DataFrame(
{
"label": ["foo", "bar", "spam"],
"a": [1, 2, 3],
"b": [10, 20, 30],
}
)
result = df.select(
pl.fold(
acc=pl.lit(0),
function=operator.add,
exprs=pl.col("a", "b"),
).alias("sum_fold"),
pl.sum_horizontal(pl.col("a", "b")).alias("sum_horz"),
)
print(result)
use polars::prelude::*;
// Contribute the Rust translation of the Python example by opening a PR.
shape: (3, 2)
┌──────────┬──────────┐
│ sum_fold ┆ sum_horz │
│ --- ┆ --- │
│ i64 ┆ i64 │
╞══════════╪══════════╡
│ 11 ┆ 11 │
│ 22 ┆ 22 │
│ 33 ┆ 33 │
└──────────┴──────────┘
The function fold
expects a function f
as the parameter function
and f
should accept two
arguments. The first argument is the accumulated result, which we initialise as zero, and the second
argument takes the successive values of the expressions listed in the parameter exprs
. In our
case, they're the two columns “a” and “b”.
The snippet below includes a third explicit expression that represents what the function fold
is
doing above:
acc = pl.lit(0)
f = operator.add
result = df.select(
f(f(acc, pl.col("a")), pl.col("b")),
pl.fold(acc=acc, function=f, exprs=pl.col("a", "b")).alias("sum_fold"),
)
print(result)
// Contribute the Rust translation of the Python example by opening a PR.
shape: (3, 2)
┌─────────┬──────────┐
│ literal ┆ sum_fold │
│ --- ┆ --- │
│ i64 ┆ i64 │
╞═════════╪══════════╡
│ 11 ┆ 11 │
│ 22 ┆ 22 │
│ 33 ┆ 33 │
└─────────┴──────────┘
fold
in Python
Most programming languages include a higher-order function that implements the algorithm that the function fold
in Polars implements.
The Polars fold
is very similar to Python's functools.reduce
.
You can learn more about the power of functools.reduce
in this article.
The initial value acc
The initial value chosen for the accumulator acc
is typically, but not always, the
identity element of the operation you want to
apply. For example, if we wanted to multiply across the columns, we would not get the correct result
if our accumulator was set to zero:
result = df.select(
pl.fold(
acc=pl.lit(0),
function=operator.mul,
exprs=pl.col("a", "b"),
).alias("prod"),
)
print(result)
// Contribute the Rust translation of the Python example by opening a PR.
shape: (3, 1)
┌──────┐
│ prod │
│ --- │
│ i64 │
╞══════╡
│ 0 │
│ 0 │
│ 0 │
└──────┘
To fix this, the accumulator acc
should be set to 1
:
result = df.select(
pl.fold(
acc=pl.lit(1),
function=operator.mul,
exprs=pl.col("a", "b"),
).alias("prod"),
)
print(result)
// Contribute the Rust translation of the Python example by opening a PR.
shape: (3, 1)
┌──────┐
│ prod │
│ --- │
│ i64 │
╞══════╡
│ 10 │
│ 40 │
│ 90 │
└──────┘
Conditional
In the case where you'd want to apply a condition/predicate across all columns in a dataframe, a fold can be a very concise way to express this.
df = pl.DataFrame(
{
"a": [1, 2, 3],
"b": [0, 1, 2],
}
)
result = df.filter(
pl.fold(
acc=pl.lit(True),
function=lambda acc, x: acc & x,
exprs=pl.all() > 1,
)
)
print(result)
// Contribute the Rust translation of the Python example by opening a PR.
shape: (1, 2)
┌─────┬─────┐
│ a ┆ b │
│ --- ┆ --- │
│ i64 ┆ i64 │
╞═════╪═════╡
│ 3 ┆ 2 │
└─────┴─────┘
The snippet above filters all rows where all columns are greater than 1.
Folds and string data
Folds could be used to concatenate string data. However, due to the materialization of intermediate columns, this operation will have squared complexity.
Therefore, we recommend using the function concat_str
for this:
df = pl.DataFrame(
{
"a": ["a", "b", "c"],
"b": [1, 2, 3],
}
)
result = df.select(pl.concat_str(["a", "b"]))
print(result)
concat_str
· Available on feature concat_str
let df = df!(
"a" => ["a", "b", "c"],
"b" => [1, 2, 3],
)?;
let result = df
.lazy()
.select([concat_str([col("a"), col("b")], "", false)])
.collect()?;
println!("{:?}", result);
shape: (3, 1)
┌─────┐
│ a │
│ --- │
│ str │
╞═════╡
│ a1 │
│ b2 │
│ c3 │
└─────┘